简单的互斥用法
POSIX 线程库提供互斥原语的实现,用于互斥。互斥是使用 pthread_mutex_init
创建的,并使用 pthread_mutex_destroy
销毁。可以使用 pthread_mutex_lock
或 pthread_mutex_trylock
来获取互斥锁 (取决于是否需要超时)并通过 pthread_mutex_unlock
释放互斥锁。
下面是一个使用互斥锁来序列化对关键部分的访问的简单示例。首先,不使用互斥锁的示例。请注意,由于两个线程对 global_resource
的不同步访问,此程序存在数据争用。因此,此程序具有未定义的行为 :
#include <pthread.h>
#include <unistd.h>
#include <stdio.h>
#include <errno.h>
#include <stdlib.h>
// Global resource accessible to all threads
int global_resource;
// Threading routine which increments the resource 10 times and prints
// it after every increment
void* thread_inc (void* arg)
{
for (int i = 0; i < 10; i++)
{
global_resource++;
printf("Increment: %d\n", global_resource);
// Make this thread slower, so the other one
// can do more work
sleep(1);
}
printf("Thread inc finished.\n");
return NULL;
}
// Threading routine which decrements the resource 10 times and prints
// it after every decrement
void* thread_dec (void* arg)
{
for (int i = 0; i < 10; i++)
{
global_resource--;
printf("Decrement: %d\n", global_resource);
}
printf("Thread dec finished.\n");
return NULL;
}
int main (int argc, char** argv)
{
pthread_t threads[2];
if (0 != (errno = pthread_create(&threads[0], NULL, thread_inc, NULL)))
{
perror("pthread_create() failed");
return EXIT_FAILURE;
}
if (0 != (errno = pthread_create(&threads[1], NULL, thread_dec, NULL)))
{
perror("pthread_create() failed");
return EXIT_FAILURE;
}
// Wait for threads to finish
for (int i = 0; i < 2; i++)
{
if (0 != (errno = pthread_join(threads[i], NULL))) {
perror("pthread_join() failed");
return EXIT_FAILURE;
}
}
return EXIT_SUCCESS;
}
可能的输出是:
Increment: 1
Decrement: 0
Decrement: -1
Decrement: -2
Decrement: -3
Decrement: -4
Decrement: -5
Decrement: -6
Decrement: -7
Decrement: -8
Decrement: -9
Thread dec finished.
Increment: -8
Increment: -7
Increment: -6
Increment: -5
Increment: -4
Increment: -3
Increment: -2
Increment: -1
Increment: 0
Thread inc finished.
现在,如果我们想要同步这些线程以便我们希望首先向上或向下递增或递减,然后以不同的方式执行,我们需要使用同步原语,例如互斥:
#include <pthread.h>
#include <unistd.h>
#include <stdio.h>
#include <errno.h>
#include <stdlib.h>
// Global resource accessible to all threads
int global_resource;
// Mutex protecting the resource
pthread_mutex_t mutex;
// Threading routine which increments the resource 10 times and prints
// it after every increment
void* thread_inc (void* arg)
{
// Pointer to mutex is passed as an argument
pthread_mutex_t* mutex = arg;
// Execute the following code without interrupts, all the way to the
// point B
if (0 != (errno = pthread_mutex_lock(mutex)))
{
perror("pthread_mutex_lock failed");
exit(EXIT_FAILURE);
}
for (int i = 0; i < 10; i++)
{
global_resource++;
printf("Increment: %d\n", global_resource);
// Make this thread slower, so the other one
// can do more work
sleep(1);
}
printf("Thread inc finished.\n");
// Point B:
if (0 != (errno = pthread_mutex_unlock(mutex)))
{
perror("pthread_mutex_unlock failed");
exit(EXIT_FAILURE);
}
return NULL;
}
// Threading routine which decrements the resource 10 times and prints
// it after every decrement
void* thread_dec (void* arg)
{
// Pointer to mutex is passed as an argument
pthread_mutex_t* mutex = arg;
if (0 != (errno = pthread_mutex_lock(mutex)))
{
perror("pthread_mutex_lock failed");
exit(EXIT_FAILURE);
}
for (int i = 0; i < 10; i++)
{
global_resource--;
printf("Decrement: %d\n", global_resource);
}
printf("Thread dec finished.\n");
// Point B:
if (0 != (errno = pthread_mutex_unlock(mutex)))
{
perror("pthread_mutex_unlock failed");
exit(EXIT_FAILURE);
}
return NULL;
}
int main (int argc, char** argv)
{
pthread_t threads[2];
pthread_mutex_t mutex;
// Create a mutex with the default parameters
if (0 != (errno = pthread_mutex_init(&mutex, NULL)))
{
perror("pthread_mutex_init() failed");
return EXIT_FAILURE;
}
if (0 != (errno = pthread_create(&threads[0], NULL, thread_inc, &mutex)))
{
perror("pthread_create() failed");
return EXIT_FAILURE;
}
if (0 != (errno = pthread_create(&threads[1], NULL, thread_dec, &mutex)))
{
perror("pthread_create() failed");
return EXIT_FAILURE;
}
// Wait for threads to finish
for (int i = 0; i < 2; i++)
{
if (0 != (errno = pthread_join(threads[i], NULL))) {
perror("pthread_join() failed");
return EXIT_FAILURE;
}
}
// Both threads are guaranteed to be finished here, so we can safely
// destroy the mutex
if (0 != (errno = pthread_mutex_destroy(&mutex)))
{
perror("pthread_mutex_destroy() failed");
return EXIT_FAILURE;
}
return EXIT_SUCCESS;
}
其中一个可能的输出是
Increment: 1
Increment: 2
Increment: 3
Increment: 4
Increment: 5
Increment: 6
Increment: 7
Increment: 8
Increment: 9
Increment: 10
Thread inc finished.
Decrement: 9
Decrement: 8
Decrement: 7
Decrement: 6
Decrement: 5
Decrement: 4
Decrement: 3
Decrement: 2
Decrement: 1
Decrement: 0
Thread dec finished.
在 thread_dec
首先获得互斥锁的情况下,其他可能的输出将是反向的。