数据类型自动

此示例显示了编译器可以执行的基本类型推断。

auto a = 1;        //    a = int
auto b = 2u;       //    b = unsigned int
auto c = &a;       //    c = int*
const auto  d = c; //    d = const int*
const auto& e = b; //    e = const unsigned int& 

auto x = a + b     //    x = int, #compiler warning unsigned and signed

auto v = std::vector<int>;    //    v = std::vector<int>

但是，如果没有 & 或 const 或 constexpr 的附加提示，auto 关键字并不总是执行预期的类型推断

//    y = unsigned int, 
//    note that y does not infer as const unsigned int&
//    The compiler would have generated a copy instead of a reference value to e or b
auto y = e;